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- Here we have two variables vcount and ccount to keep the count of vowels and consonants respectively. We have converted each char of the
**string**to lowercase using toLowerCase () method for easy comparison. We are then comparing each char of the**string**to vowels ‘a’, ‘e’, ‘i’, ‘o’, ‘u’ using charAt () method and if..else..if ... **Find number**of times a**string**occurs as a subsequence in given**string**. Input:**string**a = "GeeksforGeeks"**string**b = "Gks" Output: 4 Explanation: The four**strings**are - (**Check**characters marked in bold) GeeksforGeeks GeeksforGeeks GeeksforGeeks GeeksforGeeks- This problem can be solved using Dynamic Programming in O (N) time complexity where N is the length of the
**string**. For example 1. Input: "68412" Output: 6 Explanation: Since 6, 84, 12, 684, 8412, 68412 are the only**substrings**which are**divisible by 6**. Example 2. Input: "350648" Output: 6 Explanation : 0, 6, 48, 648, 5064, 35064 are the only ... - Original
**String**: helloslkhellodjladfjhello**Sub****String**: hello Total**Number****Of****Substring**Appears: 3.**Substring**Matching In**Java**Solution 4:**Find**The**Number****of**Times**Substrings**Appear In**String**By RegularExpression. Patterns of arbitrary length; Overlapping matches (such as counting "232" in "23232" or "aa" in "aaa")